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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3472/CH9/EX9.25/Example9_25.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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diff --git a/3472/CH9/EX9.25/Example9_25.sce b/3472/CH9/EX9.25/Example9_25.sce new file mode 100644 index 000000000..7da4ececf --- /dev/null +++ b/3472/CH9/EX9.25/Example9_25.sce @@ -0,0 +1,30 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART II : TRANSMISSION AND DISTRIBUTION
+// CHAPTER 2: CONSTANTS OF OVERHEAD TRANSMISSION LINES
+
+// EXAMPLE : 2.25 :
+// Page number 120
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+d_1 = 6.0 // Distance between conductor 1 & 2(m)
+d_2 = 6.0 // Distance between conductor 2 & 3(m)
+d_3 = 12.0 // Distance between conductor 3 & 1(m)
+dia = 1.24/100 // Diameter of conductor(m)
+l = 100.0 // Length of line(km)
+
+// Calculations
+r = dia/2 // Radius of conductor(m)
+e = 8.854*10**-12 // Constant ε_0
+d = (d_1*d_2*d_3)**(1.0/3) // Distance(m)
+C = 2*%pi*e/log(d/r) // Capacitance(F/m)
+C_l = C*1000.0*l // Capacitance for entire length(F)
+C_lu = C_l*10.0**6 // Capacitance for entire length(μF)
+
+// Results
+disp("PART II - EXAMPLE : 2.25 : SOLUTION :-")
+printf("\nCapacitance of the line, C = %.3f μF", C_lu)
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