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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART IV : UTILIZATION AND TRACTION
+// CHAPTER 1: INDUSTRIAL APPLICATIONS OF ELECTRIC MOTORS
+
+// EXAMPLE : 1.14 :
+// Page number 689
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+V = 400.0 // Voltage of DC shunt motor(V)
+hp = 20.0 // Power of DC shunt motor(hp)
+I = 44.0 // Current drawn by motor(A)
+N_1 = 1000.0 // Speed(rpm)
+N_2 = 800.0 // Speed with additional resistance(rpm)
+R_sh = 200.0 // Shunt field resistance(ohm)
+
+// Calculations
+output = hp*746 // Motor output(W)
+I_f1 = V/R_sh // Shunt field current(A)
+I_a1 = I-I_f1 // Armature current(A)
+E_b1 = output/I_a1 // Back emf(V)
+R_a = (V-E_b1)/I_a1 // Armature resistance(ohm)
+I_a2 = I_a1*(N_2/N_1)**2 // Armature current at N2(A)
+E_b2 = N_2/N_1*E_b1 // Back emf at N2(V)
+r = ((V-E_b2)/I_a2)-R_a // Resistance connected in series with armature(ohm)
+
+// Results
+disp("PART IV - EXAMPLE : 1.14 : SOLUTION :-")
+printf("\nResistance to be connected in series with armature to reduce speed, r = %.2f ohm", r)