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authorprashantsinalkar2017-10-10 12:27:19 +0530
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+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 8: PROTECTION OF ALTERNATORS AND AC MOTORS
+
+// EXAMPLE : 8.1 :
+// Page number 624
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+V = 6600.0 // Alternator Voltage(V)
+P = 2000.0*10**3 // Rating of alternator(W)
+PF = 0.8 // Power factor of alternator
+X = 12.5 // Alternator reactance(%)
+I = 200.0 // Current protection(A)
+per = 10.0 // Percentage of winding unprotected(%)
+
+// Calculations
+I_fl = P/(3**0.5*V*PF) // Full load current of alternator(A)
+x = X*V/(3**0.5*100*I_fl) // Reactance per phase of alternator(ohm)
+x_per = per/100*x // Reactance of 10% of the winding(ohm)
+NA = V/(3**0.5*per) // Voltage induced in winding(V)
+r = ((NA/I)**2-x_per**2)**0.5 // Neutral earthing reactance(ohm)
+
+// Results
+disp("PART III - EXAMPLE : 8.1 : SOLUTION :-")
+printf("\nNeutral earthing reactance, r = %.2f ohm", r)