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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3472/CH3/EX3.4/Example3_4.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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initial commit / add all books
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diff --git a/3472/CH3/EX3.4/Example3_4.sce b/3472/CH3/EX3.4/Example3_4.sce new file mode 100644 index 000000000..a5a7cb173 --- /dev/null +++ b/3472/CH3/EX3.4/Example3_4.sce @@ -0,0 +1,26 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART I : GENERATION
+// CHAPTER 3: HYDRO-ELECTRIC STATIONS
+
+// EXAMPLE : 3.4 :
+// Page number 41-42
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+load_factor = 0.15 // Load factor
+P = 10.0*10**3 // Rated installed capacity(kW)
+H = 50.0 // Head of plant(m)
+n = 0.8 // Efficiency of plant
+
+//Calculation
+units_day = P*load_factor // Total units generated daily on basis of load factor(kWhr)
+units_week = units_day*24.0*7 // Total units generated for one week(kWhr)
+Q = units_week/(9.81*H*n*24*7) // Minimum flow of water(cubic mt/sec)
+
+//Result
+disp("PART I - EXAMPLE : 3.4 : SOLUTION :-")
+printf("\nMinimum flow of river water to operate the plant, Q = %.3f cubic mt/sec", Q)
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