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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3472/CH29/EX29.7/Example29_7.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
| download | Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.gz Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.bz2 Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.zip | |
initial commit / add all books
Diffstat (limited to '3472/CH29/EX29.7/Example29_7.sce')
| -rw-r--r-- | 3472/CH29/EX29.7/Example29_7.sce | 45 |
1 files changed, 45 insertions, 0 deletions
diff --git a/3472/CH29/EX29.7/Example29_7.sce b/3472/CH29/EX29.7/Example29_7.sce new file mode 100644 index 000000000..9d5c41dc6 --- /dev/null +++ b/3472/CH29/EX29.7/Example29_7.sce @@ -0,0 +1,45 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART III : SWITCHGEAR AND PROTECTION
+// CHAPTER 3: SYMMETRICAL COMPONENTS' ANALYSIS
+
+// EXAMPLE : 3.7 :
+// Page number 492-493
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+V = 2300.0 // Rated voltage(V)
+kVA = 500.0 // kVA rating
+I_1 = 100.0 // Line current(A)
+I_2 = 100.0*exp(%i*180*%pi/180) // Line current(A)
+I_3 = 0 // Line current(A)
+
+// Calculations
+a = exp(%i*120.0*%pi/180) // Operator
+I_10 = 1.0/3*(I_1+I_2+I_3) // Symmetrical component of line current for phase 1(A)
+I_11 = 1.0/3*(I_1+a*I_2+a**2*I_3) // Symmetrical component of line current for phase 1(A)
+I_12 = 1.0/3*(I_1+a**2*I_2+a*I_3) // Symmetrical component of line current for phase 1(A)
+I_20 = I_10 // Symmetrical component of line current for phase 2(A)
+I_21 = a**2*I_11 // Symmetrical component of line current for phase 2(A)
+I_22 = a*I_12 // Symmetrical component of line current for phase 2(A)
+I_30 = I_10 // Symmetrical component of line current for phase 3(A)
+I_31 = a*I_11 // Symmetrical component of line current for phase 3(A)
+I_32 = a**2*I_12 // Symmetrical component of line current for phase 3(A)
+
+// Results
+disp("PART III - EXAMPLE : 3.7 : SOLUTION :-")
+printf("\nSymmetrical component of line current for phase 1:")
+printf("\n I_10 = %.1f A", abs(I_10))
+printf("\n I_11 = %.2f∠%.f° A", abs(I_11),phasemag(I_11))
+printf("\n I_12 = %.2f∠%.f° A", abs(I_12),phasemag(I_12))
+printf("\nSymmetrical component of line current for phase 2:")
+printf("\n I_20 = %.1f A", abs(I_20))
+printf("\n I_21 = %.2f∠%.f° A", abs(I_21),phasemag(I_21))
+printf("\n I_22 = %.2f∠%.f° A", abs(I_22),phasemag(I_22))
+printf("\nSymmetrical component of line current for phase 3:")
+printf("\n I_30 = %.1f A", abs(I_30))
+printf("\n I_31 = %.2f∠%.f° A", abs(I_31),phasemag(I_31))
+printf("\n I_32 = %.2f∠%.f° A", abs(I_32),phasemag(I_32))
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