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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART II : TRANSMISSION AND DISTRIBUTION
+// CHAPTER 13: WAVE PROPAGATION ON TRANSMISSION LINES
+
+// EXAMPLE : 13.6 :
+// Page number 367
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+Z = 100.0 // Surge impedance of cable(ohm)
+Z_1 = 600.0 // Surge impedance of open wire(ohm)
+Z_2 = 1000.0 // Surge impedance of open wire(ohm)
+e = 2.0 // Steep fronted voltage(kV)
+
+// Calculations
+Z_t = Z_1*Z_2/(Z_1+Z_2) // Resultant surge impedance(ohm)
+E = e*(1+((Z_t-Z)/(Z_t+Z))) // Transmitted voltage(kV)
+I_1 = E*1000/Z_1 // Current(A)
+I_2 = E*1000/Z_2 // Current(A)
+E_ref = e*(Z_t-Z)/(Z_t+Z) // Reflected voltage(kV)
+I_ref = -E_ref*1000/Z // Reflected current(A)
+
+// Results
+disp("PART II - EXAMPLE : 13.6 : SOLUTION :-")
+printf("\nVoltage in the cable = %.3f kV", E)
+printf("\nCurrent in the cable, I_1 = %.2f A", I_1)
+printf("\nCurrent in the cable, I_2 = %.3f A", I_2)
+printf("\nVoltage in the open-wire lines i.e Reflected voltage = %.3f kV", E_ref)
+printf("\nCurrent in the open-wire lines i.e Reflected current = %.2f A", I_ref)