diff options
| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /3472/CH10/EX10.21/Example10_21.sce | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
| download | Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.gz Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.bz2 Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.zip | |
initial commit / add all books
Diffstat (limited to '3472/CH10/EX10.21/Example10_21.sce')
| -rw-r--r-- | 3472/CH10/EX10.21/Example10_21.sce | 43 |
1 files changed, 43 insertions, 0 deletions
diff --git a/3472/CH10/EX10.21/Example10_21.sce b/3472/CH10/EX10.21/Example10_21.sce new file mode 100644 index 000000000..61ad2aa03 --- /dev/null +++ b/3472/CH10/EX10.21/Example10_21.sce @@ -0,0 +1,43 @@ +// A Texbook on POWER SYSTEM ENGINEERING
+// A.Chakrabarti, M.L.Soni, P.V.Gupta, U.S.Bhatnagar
+// DHANPAT RAI & Co.
+// SECOND EDITION
+
+// PART II : TRANSMISSION AND DISTRIBUTION
+// CHAPTER 3: STEADY STATE CHARACTERISTICS AND PERFORMANCE OF TRANSMISSION LINES
+
+// EXAMPLE : 3.21 :
+// Page number 153
+clear ; clc ; close ; // Clear the work space and console
+
+// Given data
+V_r = 132.0*10**3 // Line voltage at receiving end(V)
+P_L = 45.0*10**6 // Load delivered(VA)
+PF_r = 0.8 // Lagging power factor
+A = 0.99*exp(%i*0.3*%pi/180) // Constant
+B = 70.0*exp(%i*69.0*%pi/180) // Constant(ohms)
+C = A // Constant
+D = 4.0*10**-4*exp(%i*90.0*%pi/180) // Constant
+
+// Calculations
+E_r = V_r/3**0.5 // Receiving end phasemag voltage(V)
+I_r = P_L/(3**0.5*V_r)*exp(%i*-acos(PF_r)) // Line current(A)
+E_s = A*E_r+B*I_r // Sending end voltage(V)
+E_s_llkV = 3**0.5*E_s/1000.0 // Sending end line voltage(kV)
+I_s = C*I_r+D*E_r // Sending end current(A)
+angle_Er_Es = phasemag(E_s) // Angle between E_r and E_s(°)
+angle_Er_Is = phasemag(I_s) // Angle between E_r and I_s(°)
+angle_Es_Is = angle_Er_Es-angle_Er_Is // Angle between E_s and I_s(°)
+PF_s = cosd(angle_Es_Is) // Sending end power factor
+P_s = 3*abs(E_s*I_s)*PF_s // Sending end power(W)
+P_skW = P_s/1000.0 // Sending end power(kW)
+P_r = P_L*PF_r // Receiving end power(W)
+n = P_r/P_s*100 // Transmission efficiency(%)
+
+// Results
+disp("PART II - EXAMPLE : 3.21 : SOLUTION :-")
+printf("\nCase(i) : Sending end voltage, E_s = %.1f∠%.f° kV (line-to-line)", abs(E_s_llkV),phasemag(E_s_llkV))
+printf("\nCase(ii) : Sending end current, I_s = %.1f∠%.1f° A", abs(I_s),phasemag(I_s))
+printf("\nCase(iii): Sending end power, P_s = %.f kW", P_skW)
+printf("\nCase(iv) : Efficiency of transmission = %.2f percent \n", n)
+printf("\nNOTE: Changes in obtained answer from that textbook is due to more precision")
|