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authorpriyanka2015-06-24 15:03:17 +0530
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+//Example 5.1
+//Forces Between Dislocations
+//Page No. 166
+clc;clear;close;
+
+G=40; //in GPa
+G=G*10^9; //conversion to N/m^2
+b=2.5; //in angstrong
+b=b*10^-10; //conversion to m
+r=1200; //in angstrong
+r=r*10^-10; //conversion to m
+l=0.04; //in mm
+l=l*10^-3; //conversion to m
+F=G*b^2/(2*%pi*r);
+Ft=F*l;
+printf('The Total force on the dislocation is = %g N',Ft);