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authorpriyanka2015-06-24 15:03:17 +0530
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+//Section-9,Example-2,Page no.-E.9
+//To find K_eq for the given reaction.
+clc;
+E0_Ag=0.80
+E0_Cu=0.34
+E0=E0_Ag-E0_Cu //E0_cell in volt
+n=2
+F=96500
+R=8.314
+T=298
+K=(n*F*E0)/(R*T)
+//K_eq=antilog(K)
+K_eq=%e^K
+disp(K_eq,'K_eq for the given reaction')
+//Answer in the book is wrong.
+
+
+