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authorpriyanka2015-06-24 15:03:17 +0530
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+//Chapter 3, Exmaple 19, page 111
+//Determine mean free path and ionization
+clc
+clear
+//(a)Mean free path
+//Based on equation 3.14 and 3.15
+lambda = 1/(9003*0.5)
+//(b)Ionization potential
+Vi = 256584/9003
+printf("\n lambda = %e m ",lambda)
+printf("\n Vi = %f V ",Vi)
+
+//answers may vary due to round off error