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| author | priyanka | 2015-06-24 15:03:17 +0530 |
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| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /3369/CH16/EX16.8/Ex16_8.sce | |
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initial commit / add all books
Diffstat (limited to '3369/CH16/EX16.8/Ex16_8.sce')
| -rwxr-xr-x | 3369/CH16/EX16.8/Ex16_8.sce | 24 |
1 files changed, 24 insertions, 0 deletions
diff --git a/3369/CH16/EX16.8/Ex16_8.sce b/3369/CH16/EX16.8/Ex16_8.sce new file mode 100755 index 000000000..94475426e --- /dev/null +++ b/3369/CH16/EX16.8/Ex16_8.sce @@ -0,0 +1,24 @@ +//Chapter 16,Example 8,page 562 +//Determine the circuit efficiency +clear +clc +C1 = 0.125*10^-6 // F +C2 = 1*10^-9 // F +T2 = 2500 +T1 = 250 +// Bsaed on Figure 16.12 +T2T1 = T2/T1 +a = 4 // alpha +theta = T2/6 +// From table 16.1 +X = (1/a^2)*(1+C2/C1) +R1 = (a*theta*10^-6/C2)*(1-sqrt(1-X)) +R2 = (a*theta*10^-6/(C1+C2))*(1+sqrt(1-X)) +neta = 1/(1+(1+R1/R2)*C2/C1) +printf("\n Theta = %f micro S", theta) +printf("\n X = %f ", X) +printf("\n R1 = %f k Ohm", R1*10^-3) +printf("\n R2 = %f k Ohm", R2*10^-3) +printf("\n neta = %f ", neta) + +// Answers may vary due to round off error |