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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /3369/CH12/EX12.9 | |
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-rwxr-xr-x | 3369/CH12/EX12.9/Ex12_9.sce | 26 |
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diff --git a/3369/CH12/EX12.9/Ex12_9.sce b/3369/CH12/EX12.9/Ex12_9.sce new file mode 100755 index 000000000..2253390d9 --- /dev/null +++ b/3369/CH12/EX12.9/Ex12_9.sce @@ -0,0 +1,26 @@ +//Chapter 12,Example 9, page 412 +//Determine the maximum stress +clear +clc +Emax = 47.5 // kV +b = 2.65 // cm +a = 1 // cm +ba = 0.55*3 // 1/3(b-a) +r1 = 1.55 // cm +r2 = 2.1 // cm2Vr = 2.65 // cm +V = 53.8 // kV +alpha = nthroot(ba,3) +// based on the example 12_8 +//calculating VEmax1, Emax2, Emax3 +x = 1/(a*log(r1/a)) +y = 1/(r1*log(r2/r1)) +z = 1/(r2*log(b/r2)) +VV1 = Emax/x +V1V2 = Emax/y +V2 = Emax/z +V1 = V2+(Emax/y) +printf("\n Emax = %f kV/cm",Emax) +printf("\n V1 = %f kV/cm",V1) +printf("\n V2 = %f kV/cm",V2) + +// Answers may vary due to round off error. |