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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /3311/CH10/EX10.4 | |
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-rwxr-xr-x | 3311/CH10/EX10.4/Ex10_4.sce | 26 |
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diff --git a/3311/CH10/EX10.4/Ex10_4.sce b/3311/CH10/EX10.4/Ex10_4.sce new file mode 100755 index 000000000..f4c46d40f --- /dev/null +++ b/3311/CH10/EX10.4/Ex10_4.sce @@ -0,0 +1,26 @@ +// chapter 10 +// example 10.4 +// Determine the value of fundamental rms output voltage, rms output current and output power +// page-700-701 +clear; +clc; +// given +n=3/1; // transformer turn ratio +wL=3; // in ohm (inductive reactance) +R_L=4; // in ohm (load resistance) +alpha=160; // in degree (firing angle) +E=410; // in V (input voltage per phase) +f=50; // in Hz (supply frequency) +m=6; // number of pulses +// calculate +Eph=E/2; // calculation of per phase voltage to convertor +E_line=Eph*sqrt(3); // calculation of input to bridge invertor +r=cosd(180-alpha); // calculation of voltage reduction factor +Eor=r*E_line*(m/%pi)*sin(%pi/m); // calculation of fundamental rms output voltage, +Ior_magnitude=Eor/sqrt(R_L^2+wL^2); // calculation of rms output current magnitude +Ior_phase=-atand(wL/R_L); // calculation of rms output current phase +P0=Ior_magnitude^2*R_L; // calculation of output power +printf("\nThe fundamental rms output voltage is \t Eor=%.2f V",Eor); +printf("\nThe rms output current is \t Ior=%.2f A \t and phase is \t %.2f degree",Ior_magnitude,Ior_phase); +printf("\nThe output power is \t P0=%.2f W",P0); +// Note: The answers vary slightly due to precise calculation.
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