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+// chapter 2
+// example 2.3
+// Find the minimum diameter of the steel wire
+// page-16-17
+clear;
+clc;
+// given
+P=5; // in kN (Load on the steel wire)
+sigma=100; // in MPa (stress in the wire)
+// calculate
+P=P*1E3; // changing unit from kN to N
+sigma=sigma*1; // changing unit from MPa to N/mm^2
+// since stress=P/A= P/(Pi*d^2/4), therefore d can be calculated as
+d=sqrt(4*P/(%pi*sigma)); // calculation of minimum diameter of the steel wire
+printf("\nThe minimum diameter of the steel wire is \t d=%.2f mm  or %.f mm",d,d);