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authorpriyanka2015-06-24 15:03:17 +0530
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+//Page Number: 468
+//Example 9.8
+clc;
+//Given
+e=1.6D-19;
+Nd=1.1D+23; //m-3
+a=0.2D-6; //m
+er=11.8;
+e0=8.854D-12;
+mue=800D-4; //m2/Vs
+Z=50D-6;
+L=8.5D-6; //m
+W0=1; //V
+Vd=12; //V
+Vg=1.5; //V
+
+//(i) Pinch off voltage and pinch off current
+Vp=(e*Nd*a*a)/(2*er*e0);
+disp('V',Vp,'Pinch off voltage:');
+
+Ip=(mue*e*e*Nd*Nd*Z*a*a)/(e0*er*L);
+disp('A',Ip,'Pinch off current:');
+//Answer for Ip is 55809 A but it is given as 0.00558 A
+
+//(ii) Drain and maximum drain current
+//Taking Ip=5.58mA as given in book
+Ip1=0.00558; //A
+x=(2/3)*(((Vd+Vg+W0)/Vp)^(3/2));
+y=(2/3)*(((Vg+W0)/Vp)^(3/2));
+Id=Ip1*[(Vd/Vp)-x+y];
+disp('A',-Id,'Drain current:');
+
+//Saturation Current
+Is=Ip1*[(1/3)-((Vg+W0)/Vp)+((2/3)*(((Vg+W0)/Vp)^(3/2)))];
+disp('A',Is,'Drain saturation current:');
+
+//(iii) Cut off frequency
+f=(2*mue*e*Nd*a*a)/(%pi*er*e0*L*L);
+disp('GHz',f/10^9,'Cutt off freqency:');
+
+