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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /3250/CH5 | |
download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip |
initial commit / add all books
Diffstat (limited to '3250/CH5')
-rwxr-xr-x | 3250/CH5/EX5.1/Ex5_1.sce | 16 | ||||
-rwxr-xr-x | 3250/CH5/EX5.1/Ex5_1.txt | 3 | ||||
-rwxr-xr-x | 3250/CH5/EX5.2/Ex5_2.sce | 12 | ||||
-rwxr-xr-x | 3250/CH5/EX5.2/Ex5_2.txt | 4 | ||||
-rwxr-xr-x | 3250/CH5/EX5.3/Ex5_3.sce | 19 | ||||
-rwxr-xr-x | 3250/CH5/EX5.3/Ex5_3.txt | 3 | ||||
-rwxr-xr-x | 3250/CH5/EX5.4/Ex5_4.sce | 14 | ||||
-rwxr-xr-x | 3250/CH5/EX5.4/Ex5_4.txt | 3 |
8 files changed, 74 insertions, 0 deletions
diff --git a/3250/CH5/EX5.1/Ex5_1.sce b/3250/CH5/EX5.1/Ex5_1.sce new file mode 100755 index 000000000..fcfef018b --- /dev/null +++ b/3250/CH5/EX5.1/Ex5_1.sce @@ -0,0 +1,16 @@ +clc +// Given that +A = 20 // Value of A in voltage length characteristic equation +B = 40 // Value of B in voltage length characteristic equation +v= 80 // Open circuit voltage in V +I = 1000 // Short circuit current in amp +// Sample Problem 1 on page no. 285 +printf("\n # PROBLEM 5.1 # \n") +l=poly(0,"l") +i = ((v-A)-(B* l))*(I/v) +V = (A+B*l)// Given in the question +P = V*i +k = derivat(P) +L=roots(k) +Pmax=((v-A)-(B* L))*(I/v)*(A+B*L) +printf("\n Maximum power of the arc = %d kVA",Pmax/1000) diff --git a/3250/CH5/EX5.1/Ex5_1.txt b/3250/CH5/EX5.1/Ex5_1.txt new file mode 100755 index 000000000..848d6e537 --- /dev/null +++ b/3250/CH5/EX5.1/Ex5_1.txt @@ -0,0 +1,3 @@ + # PROBLEM 5.1 #
+
+ Maximum power of the arc = 20 kVA
\ No newline at end of file diff --git a/3250/CH5/EX5.2/Ex5_2.sce b/3250/CH5/EX5.2/Ex5_2.sce new file mode 100755 index 000000000..819ffb42e --- /dev/null +++ b/3250/CH5/EX5.2/Ex5_2.sce @@ -0,0 +1,12 @@ +clc +// Given that +N =25 // No. of bridges per cm^2 +r = 0.1 // Radius of bridge in mm +rho = 2e-5 // Resistivity of the material in ohm-cm +v= 5 // Applied voltage in V +// Sample Problem 2 on page no. 288 +printf("\n # PROBLEM 5.2 # \n") +Rc = 0.85*rho/(N*%pi*r*0.1) +Q = (v^2)/Rc +printf("\n Rate of heat generated per unit area = %e W/cm^2",Q) +// Answer in the book is given as 1.136e5 W/cm^2 diff --git a/3250/CH5/EX5.2/Ex5_2.txt b/3250/CH5/EX5.2/Ex5_2.txt new file mode 100755 index 000000000..52934c015 --- /dev/null +++ b/3250/CH5/EX5.2/Ex5_2.txt @@ -0,0 +1,4 @@ +
+ # PROBLEM 5.2 #
+
+ Rate of heat generated per unit area = 1.154997e+06 W/cm^2
\ No newline at end of file diff --git a/3250/CH5/EX5.3/Ex5_3.sce b/3250/CH5/EX5.3/Ex5_3.sce new file mode 100755 index 000000000..9a0c02119 --- /dev/null +++ b/3250/CH5/EX5.3/Ex5_3.sce @@ -0,0 +1,19 @@ +clc +// Given that +P = 2.5 // Power in kVA +t = 3 // Thickness of steel plate in mm +T = 85 // Percentage of total time when arc is on +alpha = 1.2e-5 // Thermal diffusivity of steel in m^2/sec +k = 43.6 // Thermal conductivity of steel in W/m-°C +theta_ = 1530 // Melting point of steel in °C +theta = 30 // Ambient temperature in °C +gama = 60 // Angle in degree +// Sample Problem on page no. 292 +printf("\n # PROBLEM 5.3 # \n") +C = T/100 +Q = C*P*10^3 +w = t/sind(gama) +theta_m = theta_ - theta +v_max = (4*alpha/(w*(10^-3)))*((Q/(8*k*theta_m*t*(10^-3)))-0.2) +printf("\n Maximum passible welding speed = %f m/sec",v_max) +// Answer in the book is given as 0.0146 m/sec diff --git a/3250/CH5/EX5.3/Ex5_3.txt b/3250/CH5/EX5.3/Ex5_3.txt new file mode 100755 index 000000000..e39d3a74a --- /dev/null +++ b/3250/CH5/EX5.3/Ex5_3.txt @@ -0,0 +1,3 @@ + # PROBLEM 5.3 #
+
+ Maximum passible welding speed = 0.015988 m/sec
\ No newline at end of file diff --git a/3250/CH5/EX5.4/Ex5_4.sce b/3250/CH5/EX5.4/Ex5_4.sce new file mode 100755 index 000000000..3a7c296fa --- /dev/null +++ b/3250/CH5/EX5.4/Ex5_4.sce @@ -0,0 +1,14 @@ +clc +// Given that +t = 1.2 // Thickness of aluminium sheet in mm +t_ = 0.25 // Adhesive thickness in mm +l = 12 // Overlapped length in mm +E = 703 // Modulus of elastisity in N/mm^2 +G = 11.9 // Shear modulus of adhesive in N/mm^2 +T_S = 0.6 // Ultimate shear stress in N/mm^2 +// Sample Problem 4 on page no. 303 +printf("\n # PROBLEM 5.4 # \n") +K = (((l^2)*G)/(2*E*t*t_))^(1/2) +T = T_S/K +printf("\n The maximum shear stress the lap joint can withstand = %f N/mm^2",T) +// Answer in the book is given as 0.274 N/mm^2 diff --git a/3250/CH5/EX5.4/Ex5_4.txt b/3250/CH5/EX5.4/Ex5_4.txt new file mode 100755 index 000000000..3d9bd9d25 --- /dev/null +++ b/3250/CH5/EX5.4/Ex5_4.txt @@ -0,0 +1,3 @@ + # PROBLEM 5.4 #
+
+ The maximum shear stress the lap joint can withstand = 0.297680 N/mm^2
\ No newline at end of file |