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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Ex5.22,Pg5.23
+clc;
+flkva=150 //Given
+Wi=1.4 //Iron loss in kW
+Wcu=1.6 //Copper loss in kW
+//(a)
+lkva=flkva*sqrt(Wi/Wcu)
+printf("\n Load kVA=%.2f kVA \n",lkva)
+//For maximum efficiency Wi=Wcu=1.4kW and pf=0.8
+n= (lkva*0.8/((lkva*0.8)+Wi+Wcu))*100
+printf("\n Efficiency=%.2f percent \n",n)
+//(b)
+n= (0.5*flkva*0.8/((0.5*flkva*0.8)+Wi+(0.5^2)*Wcu))*100
+printf("\n Efficiency=%.2f percent \n",n)
+ \ No newline at end of file