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authorpriyanka2015-06-24 15:03:17 +0530
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+// Initilization of variables
+W_a=50 // N // falling weight
+W_b=50 // N // weight on which W_a falls
+g=9.81 // m/s^2 // acc due to gravity
+m_a=W_a/g // kg // mass of W_a
+m_b=W_b/g // kg // mass of W_b
+k=2*10^3 // N/m // stiffness of spring
+h=0.075 // m // height through which W_a falls
+// The velocity of weight W_a just before the impact and after falling from a height of h is given from the eq'n, ( Principle of conservation of energy)
+v_a=sqrt(2*g*h) // m/s
+// Let the mutual velocity after the impact be v_m (i.e v_m=v'), (by principle of conservation of momentum)
+v_m=(m_a*v_a)/(m_a+m_b) // m/s
+// Initial compression of the spring due to weight W_b is given by,
+delta_st=(W_b/k)*(10^2) // cm
+// Let the total compression of the spring be delta_t, Then delta_t is found by finding the roots from the eq'n........ delta_t^2-0.1*delta_t-0.000003=0. In this eq'n let,
+a=1
+b=-0.1
+c=-0.000003
+delta_t=((-b+(sqrt(b^2-(4*a*c))))/2*a)*(10^2) // cm // we consider the -ve value
+delta=delta_t-delta_st // cm
+// Results
+clc
+printf('The compression of the spring over and above caused by the static action of weight W_a is %f cm \n',delta)