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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clear all; clc;
+//This numerical is Ex 1_3S,page 12.
+H=90
+Q=4.2//water flow rate(in m^3/s)
+n=1800
+E=0.87//efficiency
+rho=998
+g=9.81
+omega=(n*2*%pi)/60
+dp=rho*g*H
+printf('The pressure is %g N/m^2',dp)
+Ps=E*Q*dp
+printf('\n Output power is equal to %0.3f N-m/s',Ps)
+disp("After rounding off the value of output power is 3220 kW.")
+Psr=3220000//rounded off value of Ps
+Torque=Psr/omega
+printf(' The output torque is %g N-m.',Torque)
+disp("After rounding off the output torque comes out to be 17.1*10^3 N-m.")