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authorpriyanka2015-06-24 15:03:17 +0530
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+
+//Variable declaration
+C=0.01 //capacitance(uF)
+R2=15 //resistance(k ohms)
+Va2=4 //voltage(V)
+Vcc=15. //supply voltage(V)
+R1=33 //resistance(k ohms)
+
+//Calculations
+Va1=0.67*Vcc //voltage(V)
+Vamax=Va1+Va2 //Va maximum(V)
+Vamin=Va1-Va2 //Va minimum(V)
+T1max=C*(R1+R2)*(log((1-(Vamax/(2*Vcc)))/(1-(Vamax/Vcc)))) //time period(ms)
+T1min=C*(R1+R2)*(log((1-(Vamin/(2*Vcc)))/(1-(Vamin/Vcc)))) //time period(ms)
+T2=0.693*R2*C
+fmax=1/(T1min+T2) //maximum frequency(K Hz)
+fmin=1/(T1max+T2) //miniimum frequency(K Hz)
+
+//Results
+printf ("minimum freq is %.2f",fmin)
+printf ("maximum freq is %.2f",fmax)
+printf(" (solution given in the textbook is incorrect)");