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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Variable declaration
+C=0.1 //capacitance(uF)
+R1=10 //resistance(k ohms)
+R2=2.3 //resistance(k ohms)
+Vcc=12. //supply voltage(V)
+Rl=10**3. //resistance(k ohms)
+
+//Calculations
+//Part a
+f=1/(0.693*C*(R2+R1/2)) //frequency(Hz)
+
+//Part b
+D=(1+(R2/R1))/(1+2*(R2/R1))*100 //duty cycle
+
+//Part c
+//(i)
+T1=0.693*C*(R1+R2) //time period through R1(ms)
+T2=0.693*R2*C //time period through R2(ms)
+Pavg=(Vcc/Rl)**2*(T1/(T1+T2)) //average power dissipated during current sourcing(mW)
+
+//Part d
+Pavg1=(T2/(T1+T2))*(Vcc/Rl)**2 //average power dissipated during current sinking(mW)
+
+//Results
+printf (" %.2f kHz",f)
+printf ("duty cycle is %.2f %%",D)
+printf ("average power dissipated in current sourcing is %.3f mW",Pavg/1E-3)
+printf ("average power dissipated in current sinking is %.3f mW",Pavg1/1e-3)