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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /3012/CH7/EX7.3/Ex7_3.sce | |
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-rwxr-xr-x | 3012/CH7/EX7.3/Ex7_3.sce | 47 |
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diff --git a/3012/CH7/EX7.3/Ex7_3.sce b/3012/CH7/EX7.3/Ex7_3.sce new file mode 100755 index 000000000..1055014ad --- /dev/null +++ b/3012/CH7/EX7.3/Ex7_3.sce @@ -0,0 +1,47 @@ +// Given :- +T = 373.15 // initial temperature of saturated liquid in kelvin +T0 = 293.15 // in kelvin +P0 = 1.014 // in bar + +// Part(a) +// From table A-2 +ug = 2506.5 // in kj/kg +uf = 418.94 // in kj/kg +vg = 1.673 // in m^3/kg +vf = 1.0435*(10**(-3)) // in m^3/kg +sg = 7.3549 // in kj/kg.k +sf = 1.3069 // in kj/kg.k + + +// Calculations +// Energy transfer accompanying work +etaw = 0 // since p = p0 +// Exergy transfer accompanying heat +Q = 2257 // in kj/kg,obtained from example 6.1 +etah = (1-(T0/T))*Q + +// Exergy destruction +ed = 0 // since the process is accomplished without any irreversibilities +deltae = ug-uf + P0*(10**5)*(vg-vf)/(10**3)-T0*(sg-sf) + +// Results +printf( ' Part(a)the change in exergy is %.2f kJ/kg.',deltae) +printf( ' The exergy transfer accompanying work is %.2f kJ/kg.',etaw) +printf( ' The exergy transfer accompanying heat is %.2f kJ/kg',etah) +printf( ' The exergy destruction is %.2f kJ/kg.',ed) + + +// Part(b) +Deltae = deltae // since the end states are same +Etah = 0 // since process is adiabatic +// Exergy transfer along work +W = -2087.56 // in kj/kg from example 6.2 +Etaw = W- P0*(10**5)*(vg-vf)/(10**3) +// Exergy destruction +Ed = -(Deltae+Etaw) + +// Results +printf( ' Part(b)the change in exergy is %.2f kJ/kg.',Deltae) +printf( ' The exergy transfer accompanying work is %.2f kJ/kg.',Etaw) +printf( ' The exergy transfer accompanying heat is %.2f kJ/kg.',Etah) +printf( ' The exergy destruction is %.2f kJ/kg.',Ed) |