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+//caption:stability_using_Nyquist_criterion
+//example 12_23_i
+//page 535
+clf();
+s=%s;
+s1=-s;
+disp("for K=0.1")
+g=(0.1*(s+10)*(s+40))/(s*(s+1)*(s+4));
+g1=(0.1*(s1+10)*(s1+40))/(s1*(s1+1)*(s1+4));
+GH=syslin('c',g);
+GH1=syslin('c',g1);
+nyquist(GH);
+nyquist(GH1);
+//mtlb_axis([-1.5 0.2 -0.3 0.3]);
+xtitle('Nyquist plot of (0.1*(s+10)*(s+40))/(s*(s+1)*(s+4))')
+figure;
+show_margins(GH,'nyquist')
+disp("since the point(-1+%i0) is  not encircled clockwise by Nyquist plot ,so N=0 and P=0")
+N=0;//no. of encirclement of -1+%i0 by G(s)H(s) plot anticlockwise
+P=0;//no. of poles of G(s)H(s) with positive real part
+Z=P-N;//np.of zeros of 1+G(s)H(s)=0 with positive real part
+disp(Z,"Z=")
+disp("as Z=0,there are no roots of closed loop characterstics eq having positive real part, hence system is stable.")
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