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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Tested on Windows 7 Ultimate 32-bit
+//Chapter 7 Field Effect Transistors Pg no. 220
+clear;
+clc;
+
+//Given Data
+//Figure 7.7
+
+IDSS=15D-3;//drain saturation current in amperes
+VGS_cutoff=-5;//gate to source cutoff voltage in volts
+RD=300;//drain resistance in ohms
+
+//Solution
+
+VP=-VGS_cutoff;//pinch-off voltage in volts
+VDS=VP;//drain to source voltage in volts should be equal to VP or more than that for constant current region
+VGS=0;//gate to source voltage in volts
+ID=IDSS;//drain current in amperes is saturation current because VGS=0 volts
+VRD=ID*RD;//voltage drop across resistor
+VD_dash_min=VRD+VDS;//minimum source voltage required for constant current region in volts
+printf("Minimum VD'' required to place JFET into constant current region = %.1f Volts\n ",VD_dash_min);
+VD_dash=15;//given value of VD'
+if VD_dash>VD_dash_min then
+ ID=IDSS;//drain current in equal to saturation current
+end
+printf("Drain current for VD'' = %d Volts , ID = %d mA\n And increased voltage will appear as drop in drain source terminals.",VD_dash,ID*1000);