initial commit / add all books

11 files changed, 233 insertions, 0 deletions

diff --git a/2882/CH1/EX1.1/Ex1_1.sce b/2882/CH1/EX1.1/Ex1_1.sce
new file mode 100755
index 000000000..e5236cb18
--- /dev/null
+++ b/2882/CH1/EX1.1/Ex1_1.sce
@@ -0,0 +1,22 @@
+//Tested on Windows 7 Ultimate 32-bit

+//Chapter 1 Introduction to Electronics Pg no. 8

+clear;

+clc;

+

+//Given Data

+

+//Colour coding of four band resistor

+//Given Sequence: [Gray Red Red Gold]

+gray=8;

+red=2;

+gold=0.05;

+

+//Solution

+

+R=(gray*10+red)*(10^(red));//Base resistance in ohms

+R_min=R*(1-0.05);//Least possible resistance in ohms using variance

+R_max=R*(1+0.05);//Most possible resistance in ohms using variance

+

+printf("Resistance should be in between %d ohms and %d ohms",R_min,R_max);

+//Error in textbook as 5% of 8200 is 410 and not 41

+

diff --git a/2882/CH1/EX1.10/Ex1_10.sce b/2882/CH1/EX1.10/Ex1_10.sce
new file mode 100755
index 000000000..83dcd27b5
--- /dev/null
+++ b/2882/CH1/EX1.10/Ex1_10.sce
@@ -0,0 +1,16 @@
+//Tested on Windows 7 Ultimate 32-bit

+//Chapter 1 Introduction to Electronics Pg no. 33

+//Solved Problem 3

+clear;

+clc;

+

+//Given Data

+

+R=120;//resistance in ohms

+P=1000;//power in watts

+

+//Solution

+

+I=sqrt(P/R);//current in amperes

+

+printf("I=%.2f Amperes.",I);//Displaying upto 2 places of decimal

diff --git a/2882/CH1/EX1.11/Ex1_11.sce b/2882/CH1/EX1.11/Ex1_11.sce
new file mode 100755
index 000000000..fadc1342f
--- /dev/null
+++ b/2882/CH1/EX1.11/Ex1_11.sce
@@ -0,0 +1,16 @@
+//Tested on Windows 7 Ultimate 32-bit

+//Chapter 1 Introduction to Electronics Pg no. 33

+//Solved Problem 4

+clear;

+clc;

+

+//Given Data

+

+R=10;//resistance in ohms

+P=4;//power in watts

+

+//Solution

+

+I=sqrt(P/R);//current in amperes

+

+printf("Maximum safe current is I=%.3f Amperes.",I);//Displaying upto 3 places of decimal

diff --git a/2882/CH1/EX1.12/Ex1_12.sce b/2882/CH1/EX1.12/Ex1_12.sce
new file mode 100755
index 000000000..1782ce750
--- /dev/null
+++ b/2882/CH1/EX1.12/Ex1_12.sce
@@ -0,0 +1,44 @@
+//Tested on Windows 7 Ultimate 32-bit

+//Chapter 1 Introduction to Electronics Pg no. 33 and 34

+//Solved Problem 5

+clear;

+clc;

+

+//Given Data

+//Figure 1.34

+

+Rm=2;//resistance of motor in ohms

+V=10;//battery voltage in volts

+Rpot=10;//maximum resistance of potentiometer in ohms

+Ppot=100;//maximum power rating of potentiometer in watts

+

+//Solution

+

+Ipot=sqrt(Ppot/(Rpot+Rm));//maximum safe current possible through potentiometer in amperes

+printf("Current rating of potentiometer I = %.2f Amps\n\n",Ipot);

+

+Rp=10;//Resistance of potentiometer set in ohms

+I10=V/(Rp+Rm);//Current for corresponding resistance of potentiometer

+

+printf("When the potentiometer is set to %d Ohms,\nthe total resistance of the circuit is %d ohms.\n",Rp,Rp+Rm);

+printf("I = %.1f Amps\n",I10);

+

+if(I10<Ipot)

+    printf("\nThe amount of current is less than %.2f Amps and the potentiometer is safe.\n\n",Ipot);

+end

+

+

+Rp=2;//Resistance of potentiometer set in ohms

+I2=V/(Rp+Rm);//Current for corresponding resistance of potentiometer

+

+printf("When the potentiometer is set to %d Ohms,\nthe total resistance of the circuit is %d ohms\n",Rp,Rp+Rm);

+printf("I = %.1f Amps\n",I2);

+

+if(I10<Ipot)

+    printf("\nThe amount of current is less than %.2f Amps and the potentiometer is safe \n",Ipot);

+end

+

+Rp=1;//Resistance of potentiometer set in ohms

+I3=V/(Rp+Rm);//Current for corresponding resistance of potentiometer

+

+printf("\n However when potentiometer resistance is %d ohms, I= %d/%d = %.1f Amp.\nThis is greater than %.2f Amperes.\nThe potentiometer wire will get heated and temperature will rise.\nFor still lower values of potentiometer setting,\nI will be still higher and the potentiometer will be damaged.\nIt may even burn out.",Rp,V,(Rp+Rm),I3,Ipot)

diff --git a/2882/CH1/EX1.2/Ex1_2.sce b/2882/CH1/EX1.2/Ex1_2.sce
new file mode 100755
index 000000000..34161d53a
--- /dev/null
+++ b/2882/CH1/EX1.2/Ex1_2.sce
@@ -0,0 +1,22 @@
+//Tested on Windows 7 Ultimate 32-bit

+//Chapter 1 Introduction to Electronics Pg no. 9

+clear;

+clc;

+

+//Given Data

+

+//Colour coding of four band resistor

+//Given Sequence: [Orange Orange Yellow Silver]

+orange=3;

+yellow=4;

+silver=0.1;

+

+//Solution

+

+R=(orange*10+orange)*(10^(yellow));//Base resistance in ohms

+R_min=R*(1-silver);//Least possible resistance in ohms using variance

+R_max=R*(1+silver);//Most possible resistance in ohms using variance

+

+printf("Resistance should be in between %d ohms and %d ohms",R_min,R_max);

+//Error in textbook as 330K is not 33000 and is 330000

+

diff --git a/2882/CH1/EX1.3/Ex1_3.sce b/2882/CH1/EX1.3/Ex1_3.sce
new file mode 100755
index 000000000..dbba96e39
--- /dev/null
+++ b/2882/CH1/EX1.3/Ex1_3.sce
@@ -0,0 +1,23 @@
+//Tested on Windows 7 Ultimate 32-bit

+//Chapter 1 Introduction to Electronics Pg no. 9

+clear;

+clc;

+

+//Given Data

+

+//Colour coding of five band resistor

+//Given Sequence: [Yellow Gray Violet Black Green]

+yellow=4;

+gray=8;

+violet=7;

+black=0;

+green=0.005;

+

+//Solution

+

+R=(yellow*100+gray*10+violet)*(10^(black));//Base resistance in ohms

+R_min=R*(1-green);//Least possible resistance in ohms using variance

+R_max=R*(1+green);//Most possible resistance in ohms using variance

+

+printf("Resistance should be in between %.2f ohms and %.2f ohms",R_min,R_max);//Upto 2 decimal points

+//Decimal approximation error w.r.t. textbook

diff --git a/2882/CH1/EX1.4/Ex1_4.sce b/2882/CH1/EX1.4/Ex1_4.sce
new file mode 100755
index 000000000..7c58983fc
--- /dev/null
+++ b/2882/CH1/EX1.4/Ex1_4.sce
@@ -0,0 +1,18 @@
+//Tested on Windows 7 Ultimate 32-bit

+//Chapter 1 Introduction to Electronics Pg no. 12

+clear;

+clc;

+

+//Given Data

+

+area=1;//meter squares

+d=0.25;//distance between plates in centimeters

+e=8.85D-12;//permittivity of air

+

+//Solution

+

+d=d*10^-2;//converting distance into meters

+C=e*area/d;//Capacitance in Farads

+C=C*10^12;//Coverting capacitance to pF from F

+printf("C= %d pF\n",C);

+printf("The capacitor can thus store a charge of %d*10^-12 C with 1 Volt.",C);

diff --git a/2882/CH1/EX1.6/Ex1_6.sce b/2882/CH1/EX1.6/Ex1_6.sce
new file mode 100755
index 000000000..37f37cecd
--- /dev/null
+++ b/2882/CH1/EX1.6/Ex1_6.sce
@@ -0,0 +1,18 @@
+//Tested on Windows 7 Ultimate 32-bit

+//Chapter 1 Introduction to Electronics Pg no. 17

+clear;

+clc;

+

+//Given Data

+//Fig. 1.16

+

+//Solution

+blue=6;

+gray=8;

+violet=50;

+gold=0.05;

+

+C=(blue*10+gray)*10^blue*10^-12;//Capacitance in Farads

+C=C*10^6;//Converting from Farads to micro Farads

+

+printf("The value of capacitance is %d uF \n and voltage rating is %d volts and tolerance of ±%d percent.",C,violet,gold*100);

diff --git a/2882/CH1/EX1.7/Ex1_7.sce b/2882/CH1/EX1.7/Ex1_7.sce
new file mode 100755
index 000000000..d04ef4550
--- /dev/null
+++ b/2882/CH1/EX1.7/Ex1_7.sce
@@ -0,0 +1,21 @@
+//Tested on Windows 7 Ultimate 32-bit

+//Chapter 1 Introduction to Electronics Pg no. 29

+clear;

+clc;

+

+//Given Data

+//Fig 1.33

+vi=6D-3;//input volatage in volts

+Rin=1200;//input resistance in ohms

+Ai=100;//current gain

+Ro=25000;//output resistance in ohms

+Rl=1000;//load impedance

+

+//Solution

+

+is=vi/Rin;//Input current

+i2=Ai*is;//Output circuit current source value

+iL=i2*(Ro/(Ro+Rl));//Current divider to  find load current

+Vout=iL*Rl;

+

+printf("The output voltage is Vout=%.2f V",Vout);//Displaying upto 2 places of decimal

diff --git a/2882/CH1/EX1.8/Ex1_8.sce b/2882/CH1/EX1.8/Ex1_8.sce
new file mode 100755
index 000000000..4a427b073
--- /dev/null
+++ b/2882/CH1/EX1.8/Ex1_8.sce
@@ -0,0 +1,17 @@
+//Tested on Windows 7 Ultimate 32-bit

+//Chapter 1 Introduction to Electronics Pg no. 33

+//Solved Problem 1

+clear;

+clc;

+

+//Given Data

+

+wattage=100;//wattage in watts

+voltage=220;//voltage in volts

+

+//Solution

+

+I=wattage/voltage;//current in amperes

+

+printf("I=%.3f Amp.",I);//Displaying upto 3 places of decimal

+//Error due to decimal approximations

diff --git a/2882/CH1/EX1.9/Ex1_9.sce b/2882/CH1/EX1.9/Ex1_9.sce
new file mode 100755
index 000000000..158907d19
--- /dev/null
+++ b/2882/CH1/EX1.9/Ex1_9.sce
@@ -0,0 +1,16 @@
+//Tested on Windows 7 Ultimate 32-bit

+//Chapter 1 Introduction to Electronics Pg no. 33

+//Solved Problem 2

+clear;

+clc;

+

+//Given Data

+

+I=6;//current in amperes

+R=36;//resistance in ohms

+

+//Solution

+

+P=I^2*R;//power in watts

+

+printf("P=%d W.",P);