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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2873/CH8/EX8.4 | |
download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip |
initial commit / add all books
Diffstat (limited to '2873/CH8/EX8.4')
-rwxr-xr-x | 2873/CH8/EX8.4/Ex8_4.sce | 64 | ||||
-rwxr-xr-x | 2873/CH8/EX8.4/Ex8_4_1.jpg | bin | 0 -> 354230 bytes | |||
-rwxr-xr-x | 2873/CH8/EX8.4/Ex8_4_2.pdf | bin | 0 -> 227410 bytes |
3 files changed, 64 insertions, 0 deletions
diff --git a/2873/CH8/EX8.4/Ex8_4.sce b/2873/CH8/EX8.4/Ex8_4.sce new file mode 100755 index 000000000..7c33ad19c --- /dev/null +++ b/2873/CH8/EX8.4/Ex8_4.sce @@ -0,0 +1,64 @@ +// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Engineering Thermodynamics by Onkar Singh Chapter 8 Example 4")
+disp("Let us assume that the condensate leaves condenser as saturated liquid and the expansion in turbine and pumping processes are isentropic.")
+disp("from steam tables,h2=h_20MPa=3238.2 KJ/kg")
+h2=3238.2;
+disp("s2=6.1401 KJ/kg K")
+s2=6.1401;
+disp("h5=h_0.005MPa in KJ/kg")
+disp("from steam tables,at 0.005 MPa,hf=137.82 KJ/kg,hfg=2423.7 KJ/kg,sf=0.4764 KJ/kg K,sfg=7.9187 KJ/kg K")
+hf=137.82;
+hfg=2423.7;
+sf=0.4764;
+sfg=7.9187;
+disp("h5=hf+0.9*hfg in KJ/kg")
+h5=hf+0.9*hfg
+disp("s5=sf+0.9*sfg in KJ/kg K")
+s5=sf+0.9*sfg
+disp("h6=hf=137.82 KJ/kg")
+h6=137.82;
+disp("it is given that temperature at state 4 is 500 degree celcius and due to isentropic processes s4=s5=7.6032 KJ/kg K.The state 4 can be conveniently located on mollier chart by the intersection of 500 degree celcius constant temperature line and entropy value of 7.6032 KJ/kg K and the pressure and enthalpy obtained.but these shall be approximate.")
+disp("The state 4 can also be located by interpolation using steam table.The entropy value of 7.6032 KJ/kg K lies between the superheated steam states given under,p=1.20 MPa,s at 1.20 MPa=7.6027 KJ/kg K")
+disp("p=1.40 MPa,s at 1.40 MPa=7.6027 KJ/kg K")
+disp("by interpolation state 4 lies at pressure=")
+1.20+((1.40-1.20)/(7.6027-7.6759))*(7.6032-7.6759)
+disp("=1.399,approx.=1.40 MPa")
+disp("thus,steam leaves HP turbine at 1.40 MPa")
+disp("enthalpy at state 4,h4=3474.1 KJ/kg")
+h4=3474.1;
+disp("for process 2-33,s2=s3=6.1401 KJ/kg K.The state 3 thus lies in wet region as s3<sg at 1.40 MPa.Let dryness fraction at state 3 be x3.")
+s3=s2;
+disp("s3=sf+x3*sfg")
+disp("from staem tables,at 1.4 MPa,sf=2.2842 KJ/kg K,sfg=4.1850 KJ/kg K")
+sf=2.2842;
+sfg=4.1850;
+disp("so x3=(s3-sf)/sfg")
+x3=(s3-sf)/sfg
+disp("h3=hf+x3*hfg in KJ/kg")
+disp("from steam tables,at 1.4 MPa,hf=830.3 KJ/kg,hfg=1959.7 KJ/kg")
+hf=830.3;
+hfg=1959.7;
+h3=hf+x3*hfg
+disp("enthalpy at 1,h1=h6+v6*(p1-p6) in KJ/kg")
+disp("h1=hf at 0.005MPa+vf at 0.005MPa*(p1-p6)")
+disp("from steam tables, at 0.005 MPa,h6=137.82 KJ/kg,v6=0.001005 m^3/kg")
+h6=137.82;
+v6=0.001005;
+p1=20*1000;//steam entering HP turbine in KPa
+p6=0.005*1000;//condensor pressure in KPa
+h1=h6+v6*(p1-p6)
+disp("net work per kg steam=(h2-h3)+(h4-h5)-(h1-h6)in KJ/kg")
+(h2-h3)+(h4-h5)-(h1-h6)
+disp("heat added per kg of steam=(h2-h1)in KJ/kg")
+(h2-h1)
+disp("thermal efficiency=net work/heat added")
+((h2-h3)+(h4-h5)-(h1-h6))/(h2-h1)
+disp("in percentage")
+(((h2-h3)+(h4-h5)-(h1-h6))/(h2-h1))*100
+disp("pressure of steam leaving HP turbine=1.40 MPa")
+disp("thermal efficiency=56.39%")
diff --git a/2873/CH8/EX8.4/Ex8_4_1.jpg b/2873/CH8/EX8.4/Ex8_4_1.jpg Binary files differnew file mode 100755 index 000000000..ec35cc9e9 --- /dev/null +++ b/2873/CH8/EX8.4/Ex8_4_1.jpg diff --git a/2873/CH8/EX8.4/Ex8_4_2.pdf b/2873/CH8/EX8.4/Ex8_4_2.pdf Binary files differnew file mode 100755 index 000000000..fcae66b99 --- /dev/null +++ b/2873/CH8/EX8.4/Ex8_4_2.pdf |