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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2873/CH4/EX4.11 | |
download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip |
initial commit / add all books
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-rwxr-xr-x | 2873/CH4/EX4.11/Ex4_11.sce | 74 |
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diff --git a/2873/CH4/EX4.11/Ex4_11.jpg b/2873/CH4/EX4.11/Ex4_11.jpg Binary files differnew file mode 100755 index 000000000..ad0866219 --- /dev/null +++ b/2873/CH4/EX4.11/Ex4_11.jpg diff --git a/2873/CH4/EX4.11/Ex4_11.sce b/2873/CH4/EX4.11/Ex4_11.sce new file mode 100755 index 000000000..c17c1c21d --- /dev/null +++ b/2873/CH4/EX4.11/Ex4_11.sce @@ -0,0 +1,74 @@ +// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Engineering Thermodynamics by Onkar Singh Chapter 4 Example 11")
+n_carnot=0.5;//efficiency of carnot power cycle
+m=0.5;//mass of air in kg
+p2=7*10^5;//final pressure in pa
+v2=0.12;//volume in m^3
+R=287;//gas constant in J/kg K
+Q_23=40*1000;//heat transfer to the air during isothermal expansion in J
+Cp=1.008;//specific heat at constant pressure in KJ/kg K
+Cv=0.721;//specific heat at constant volume in KJ/kg K
+disp("let thermodynamic properties be denoted with respect to salient states;")
+disp("n_carnot=1-T1/T2")
+disp("so T1/T2=1-0.5")
+1-0.5
+disp("so T1/T2=0.5")
+disp("or T2=2*T1")
+disp("corresponding to state 2,p2*v2=m*R*T2")
+disp("so temperature(T2)=p2*v2/(m*R) in K")
+T2=p2*v2/(m*R)
+disp("heat transferred during process 2-3(isothermal expansion),Q_23=40 KJ")
+disp("Q_23=W_23=p2*v2*log(v3/v2)")
+disp("so volume(v3)=v2*exp(Q_23/(p2*v2)) in m^3")
+v3=v2*exp(Q_23/(p2*v2))
+disp("temperature at state 1,T1=T2/2 in K")
+T1=T2/2
+disp("during process 1-2,T2/T1=(p2/p1)^((y-1)/y)")
+disp("here expansion constant(y)=Cp/Cv")
+y=Cp/Cv
+disp("so pressure(p1)=p2/(T2/T1)^(y/(y-1)) in pa")
+p1=p2/(T2/T1)^(y/(y-1))
+disp("p1 in bar")
+p1=p1/10^5
+disp("thus p1*v1=m*R*T1")
+disp("so volume(v1)=m*R*T1/(p1*10^5) in m^3")
+v1=m*R*T1/(p1*10^5)
+disp("heat transferred during process 4-1(isothermal compression)shall be equal to the heat transferred during process2-3(isothermal expansion).")
+disp("for isentropic process,dQ=0,dW=dU")
+disp("during process 1-2,isentropic process,W_12=-m*Cv*(T2-T1)in KJ")
+disp("Q_12=0,")
+W_12=-m*Cv*(T2-T1)
+disp("W_12=-105.51 KJ(-ve work)")
+disp("during process 3-4,isentropic process,W_34=-m*Cv*(T4-T3)in KJ")
+disp("Q_31=0,")
+T4=T1;
+T3=T2;
+W_34=-m*Cv*(T4-T3)
+disp("ANS:")
+disp("W_34=+105.51 KJ(+ve work)")
+disp("so for process 1-2,heat transfer=0,work interaction=-105.51 KJ")
+disp("for process 2-3,heat transfer=40 KJ,work intercation=40 KJ")
+disp("for process 3-4,heat transfer=0,work interaction=+105.51 KJ")
+disp("for process 4-1,heat transfer=-40 KJ,work interaction=-40 KJ")
+disp("maximum temperature of cycle=585.36 KJ")
+disp("minimum temperature of cycle=292.68 KJ")
+disp("volume at the end of isothermal expansion=0.1932 m^3")
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