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authorpriyanka2015-06-24 15:03:17 +0530
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+// Display mode
+mode(0);
+// Display warning for floating point exception
+ieee(1);
+clear;
+clc;
+disp("Engineering Thermodynamics by Onkar Singh Chapter 12 Example 8")
+mc=20;//mass of oil in kg/min
+Tc_out=100;//initial temperature of oil in degree celcius
+Th_in=30;//final temperature of oil in degree celcius
+Th_out=25;//temperature of water in degree celcius
+Cpc=2;//specific heat of oil in KJ/kg K
+Cph=4.18;//specific heat of water in KJ/kg K
+mh=15;//water flow rate in kg/min
+U=25;//overall heat transfer coefficient in W/m^2 K
+disp("This oil cooler has arrangement similar to a counter flow heat exchanger.")
+disp("by heat exchanger,Q=U*A*LMTD=mc*Cpc*(Tc_out-Th_in)=mh*Cph*(Tc_in-Th_out)")
+disp("so Q in KJ/min")
+Q=mc*Cpc*(Tc_out-Th_in)
+disp("and T=Th_out+(Q/(mh*Cph))in degree celcius")
+T=Th_out+(Q/(mh*Cph))
+disp("LMTD=(deltaT_in-deltaT_out)/log(deltaT_in/deltaT_out)in degree ")
+disp("here deltaT_in=Tc_out-T in degree celcius")
+deltaT_in=Tc_out-T
+disp("deltaT_out=Th_in-Th_out in degree celcius")
+deltaT_out=Th_in-Th_out
+disp("so LMTD in degree celcius")
+LMTD=(deltaT_in-deltaT_out)/log(deltaT_in/deltaT_out)
+disp("substituting in,Q=U*A*LMTD")
+disp("A=(Q*10^3/60)/(U*LMTD)in m^2")
+A=(Q*10^3/60)/(U*LMTD)
+disp("so surface area=132.85 m^2")