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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//chapter 2
+//Etheta=60Im/r*(cos(pi/2cos(theta))/sin(theta));
+//theta=90
+//Pavg=Rrad*Irms^2;
+//Irms=Im/sqrt(2)
+printf("\n");
+Im=100*10^-3;
+r=100
+Etheta=(60*10^-3);
+H=(60*10^-3)/(120*(%pi));
+Pavg=73*(10^-1/sqrt(2))^2;//Rrad=73ohm for half wave dipole
+printf("the average power is %gW",Pavg);