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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//chapter 2
+printf("\n");
+Gt=1.5;
+Gr=1.5;
+d=10;
+Pt=15;
+f=10^9;
+c=3*10^8;
+lamda=c/f;
+Pr=Pt*Gt*Gr*(lamda/(4*(%pi)*d))^2;
+printf("the radiated power is %gW",Pr);