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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//chapter 2
+//Etheta=60*Im*cos(pi/2*cos(theta)/sin(theta))/r
+printf("\n");
+r=500*10^3;
+Etheta=10*10^-6;
+Im=Etheta*r/60;
+printf("the current through the dipole is %gA",Im);