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authorpriyanka2015-06-24 15:03:17 +0530
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+// Chapter 9_The bipolar transistor
+//Caption_Transistor cut off frequency
+//Ex_12//page 403
+Ie=0.001 //emitter current
+Cje=10^-12
+xb=0.5*10^-4
+vs=10^7
+Dn=25
+xdc=2.4*10^-4
+rc=20
+Cu=0.1*10^-12 //B-C junction capacitance
+Cs=0.1*10^-12 //collector to substrate capacitance
+re=0.0259/Ie
+tau_e=re*Cje*10^12 //emitter base junction charging time
+tau_b=(xb^2)/(2*Dn) *10^12 //base transit time
+tau=xdc/vs*10^12
+tau_c=rc*(Cu+Cs)*10^12
+tau_ec=(tau_e+tau_b+tau+tau_c) //total emitter to collector time delay
+fT=(10^3)/(2*%pi*tau_ec)
+bet=100
+fB=fT/bet //beta cutoff frrequency
+printf('Emitter to collector transit time is %1.1f psec and cut off frequency is %1.2f GHz',tau_ec,fT)
+
+