updated the code

1 files changed, 65 insertions, 64 deletions

diff --git a/278/CH11/EX11.16/ex_11_16.sce b/278/CH11/EX11.16/ex_11_16.sce
index f3fd72014..1b47e2497 100755
--- a/278/CH11/EX11.16/ex_11_16.sce
+++ b/278/CH11/EX11.16/ex_11_16.sce
@@ -1,64 +1,65 @@
-//find a.)dia of fixing bolts,b.)dimension of arms

-clc

-//soltuion

-//given

-//refer fig 11.39

-W=10000//N

-q=60//deg

-f1=100//N/mm^2

-t=60//N/mm^2

-Wh=W*sin(%pi/3)//N

-printf("the horizontal component is,%f N\n",Wh)

-Wv=W*cos(pi/3)//N

-printf("the vertical component is,%f N\n",Wv)

-Wt1=Wh/4//force on each bolt//N

-printf("the direct tensile load on each bolt is,%f N\n",Wt1)

-x1=0.05//m//distance of horizontal component from CG

-Th=Wh*x1//N-m//torque due to horizntl compnt

-Ws=Wv/4//N//shear load on each bolt

-printf("shear load on each boltis,%f N\n",Ws)

-x2=0.3//m

-Tv=Wv*x2//N-m

-Tn=Tv-Th//N-m//net moment

-printf("net moment is,%f N-m\n",Tn)

-L1=(250-175)/2000//m//dis btw 1 and 2 bolt

-L3=L1+0.175//m//dis btw 3 and 4 bolt

-printf("the value of L3 is,%f m\n",L3)

-//let w be load  on each bolt

-//Te=2*(w*L1)*L1 + 2*(w*L2)*L2=2*w(L1^2 +L2^2)//total moment abt E

-//Te=0.093*w//N-m

-w=Tn/0.093//N/m

-printf("the laod on each per meter distance from E is,%f N/m\n",w)

-L2=180//mm

-Wt2=w*L3//N

-printf("the value of Wt1 is ,%f N\n",Wt1)

-printf("the value of Wt2 is,%f N\n",Wt2)

-Wt=Wt1+Wt2//N

-printf("the value of total force is,%f N\n",Wt)

-Wte=0.5*[Wt + sqrt(Wt^2 + 4*Ws^2)]//N

-printf("the value of equivalent force is,%f N\n",Wte)

-//let dc be core dia

-dc=sqrt((4*Wte)/(pi*f1))//mm

-printf("the value of core dia is,%f mm\n",dc)

-printf("the valuf of core dia from tabl 11.1 instandard condition is 8.18mm\n")

-//let t be thickness and b be the width,b=3*t

-//A=3*b*t=9*t^2//mm^2

-//I={[b*(2*t +b)^3]/12}-{(b-t)*b^3/12}

-//I=321*t^4/12

-//Z=I/(t+0.5*b)=10.7*t^3//mm^3

-//ft1=Wh/A=962/t^2//N/mm^2

-Mh=Wh*0.05//N-m

-//ft2=Mh/Z=40.5*10^3/t^3//N/mm^2

-//Ty=Wv/A=556/t^3//N/mm^2

-Mv=Wv*0.3//N-m

-//ft3=Mv/Z=140.2*10^3/t^3//N/mm^2

-//Ftnet=ft1-ft2+ft3//N/mm^2

-//Ftnet=(962/t^2)-(40.5*10^3/t^3)+(140.210^3/t^3)

-//Ftnet=(962/t^2)+(99.7*10^3/t^3)

-Ftnet=100//N/mm^2

-//by hit and trial

-//'Ftnet=100=(962/t^2)+(99.7*10^3/t^3)

-t=10.4//mm

-b=3*t//mm

-printf("the thickness is,%f mm\n",t)

-printf("the width is,%f mm",b)

+//find a.)dia of fixing bolts,b.)dimension of arms
+clc
+//soltuion
+//given
+//refer fig 11.39
+pi = %pi;
+W=10000//N
+q=60//deg
+f1=100//N/mm^2
+t=60//N/mm^2
+Wh=W*sin(%pi/3)//N
+printf("the horizontal component is,%f N\n",Wh)
+Wv=W*cos(pi/3)//N
+printf("the vertical component is,%f N\n",Wv)
+Wt1=Wh/4//force on each bolt//N
+printf("the direct tensile load on each bolt is,%f N\n",Wt1)
+x1=0.05//m//distance of horizontal component from CG
+Th=Wh*x1//N-m//torque due to horizntl compnt
+Ws=Wv/4//N//shear load on each bolt
+printf("shear load on each boltis,%f N\n",Ws)
+x2=0.3//m
+Tv=Wv*x2//N-m
+Tn=Tv-Th//N-m//net moment
+printf("net moment is,%f N-m\n",Tn)
+L1=(250-175)/2000//m//dis btw 1 and 2 bolt
+L3=L1+0.175//m//dis btw 3 and 4 bolt
+printf("the value of L3 is,%f m\n",L3)
+//let w be load  on each bolt
+//Te=2*(w*L1)*L1 + 2*(w*L2)*L2=2*w(L1^2 +L2^2)//total moment abt E
+//Te=0.093*w//N-m
+w=Tn/0.093//N/m
+printf("the laod on each per meter distance from E is,%f N/m\n",w)
+L2=180//mm
+Wt2=w*L3//N
+printf("the value of Wt1 is ,%f N\n",Wt1)
+printf("the value of Wt2 is,%f N\n",Wt2)
+Wt=Wt1+Wt2//N
+printf("the value of total force is,%f N\n",Wt)
+Wte=0.5*[Wt + sqrt(Wt^2 + 4*Ws^2)]//N
+printf("the value of equivalent force is,%f N\n",Wte)
+//let dc be core dia
+dc=sqrt((4*Wte)/(pi*f1))//mm
+printf("the value of core dia is,%f mm\n",dc)
+printf("the valuf of core dia from tabl 11.1 instandard condition is 8.18mm\n")
+//let t be thickness and b be the width,b=3*t
+//A=3*b*t=9*t^2//mm^2
+//I={[b*(2*t +b)^3]/12}-{(b-t)*b^3/12}
+//I=321*t^4/12
+//Z=I/(t+0.5*b)=10.7*t^3//mm^3
+//ft1=Wh/A=962/t^2//N/mm^2
+Mh=Wh*0.05//N-m
+//ft2=Mh/Z=40.5*10^3/t^3//N/mm^2
+//Ty=Wv/A=556/t^3//N/mm^2
+Mv=Wv*0.3//N-m
+//ft3=Mv/Z=140.2*10^3/t^3//N/mm^2
+//Ftnet=ft1-ft2+ft3//N/mm^2
+//Ftnet=(962/t^2)-(40.5*10^3/t^3)+(140.210^3/t^3)
+//Ftnet=(962/t^2)+(99.7*10^3/t^3)
+Ftnet=100//N/mm^2
+//by hit and trial
+//'Ftnet=100=(962/t^2)+(99.7*10^3/t^3)
+t=10.4//mm
+b=3*t//mm
+printf("the thickness is,%f mm\n",t)
+printf("the width is,%f mm",b)
\ No newline at end of file