updated the code

1 files changed, 24 insertions, 24 deletions

diff --git a/278/CH10/EX10.16/ex_10_16.sce b/278/CH10/EX10.16/ex_10_16.sce
index 65cd4e992..c4a924df2 100755
--- a/278/CH10/EX10.16/ex_10_16.sce
+++ b/278/CH10/EX10.16/ex_10_16.sce
@@ -1,25 +1,25 @@
-//find size of fillet welds at top and bottom

-clc

-//solution

-//given

-//ref fig 10.34

-P=15000//N

-t=150//N/mm^2

-l=25//mm

-//Pva+Pvb=P,Pva=Pvb

-Pva=P/2//N

-Pvb=P/2//N

-//balnce moments abt B

-Pha=(P*50)/75//N

-//let s1 be size at top

-Pa=sqrt(Pva^2+Pha^2)//N

-printf("the value of force at A is,%f N\n",Pa)

-//Pa=thorat area* permissible stress

-//Pa=0.707*s1*l*t=0.707*s1*25*150=2650*s1

-s1=Pa/2650//mm

-printf("the size of weld at top is,%f mm\n",s1)

-//let s2 be size at bottom

-//Pvb=0.707*s2*l*t

-//Pvb=2650*s2

-s2=Pvb/2650//mm

+
+clc
+//solution
+//given
+//ref fig 10.34
+P=15000//N
+t=150//N/mm^2
+l=25//mm
+//Pva+Pvb=P,Pva=Pvb
+Pva=P/2//N
+Pvb=P/2//N
+//balnce moments abt B
+Pha=(P*50)/75//N
+//let s1 be size at top
+Pa=sqrt(Pva^2+Pha^2)//N
+printf("the value of force at A is,%f N\n",Pa)
+//Pa=thorat area* permissible stress
+//Pa=0.707*s1*l*t=0.707*s1*25*150=2650*s1
+s1=Pa/2650//mm
+printf("the size of weld at top is,%f mm\n",s1)
+//let s2 be size at bottom
+//Pvb=0.707*s2*l*t
+//Pvb=2650*s2
+s2=Pvb/2650//mm
 printf("the size of weld at bottom is,%f mm\n",s2)
\ No newline at end of file