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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Transport Processes and Seperation Process Principles
+//Chapter 6
+//Example 6.2-5
+//Principles of Mass Transfer
+//given data
+//si units
+P1=1;
+T1=0+273;
+Mb=74.1;//
+Ma=29;
+k=0
+X=[4 10 1;16.5 1.98 5.48];
+for i=1:3
+ s=X(1,i)*X(2,i);
+ k=k+s;
+end
+sumvb=20.1;
+Dab1=((1/(10^7))*(T1^1.75)*(((1/Ma)+(1/Mb))^0.5))/(P1*((k^(1/3))+(sumvb^(1/3)))^2);
+mprintf("i) Diffusivity= %f m2/s",Dab1)
+T2=25.9+273;
+Dab2=((1/(10^7))*(T2^1.75)*(((1/Ma)+(1/Mb))^0.5))/(P1*((k^(1/3))+(sumvb^(1/3)))^2);
+mprintf("ii) Diffusivity= %f m2/s",Dab2);
+T3=0+273;P3=2;
+Dab3=((1/(10^7))*(T3^1.75)*(((1/Ma)+(1/Mb))^0.5))/(P3*((k^(1/3))+(sumvb^(1/3)))^2);
+mprintf("iii) Diffusivity= %f m2/s",Dab3)