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authorpriyanka2015-06-24 15:03:17 +0530
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+//Transport Processes and Seperation Process Principles
+//Chapter 3
+//Example 3.2-1
+//Principles of Momentum Transfer and Applications
+//given data
+rho=1.043;//density of air at 328.5K in kg/m3
+v=23;//velocity of air in m/s
+D=0.6;//diameter of a cylinder
+mu=2.03/100000;//viscosity of air Pa.s
+delh=0.205;// 0.205m of water pitot tube reading
+rhow=1000;//density of water
+delP=delh*(rhow-rho)*9.80665;//pressure diff and g=9.80655 m/s2
+patm=101325;//atm pressure in pascals
+p1=patm+0.02008*100000;//absolute pressure+ pressure diff
+rhoc=(p1/patm)*1.043;//corrected air density
+delH=10.7/1000;//manometer reading, m of water
+Cp=0.98;
+delP=delH*(rhow-rhoc)*9.80655;//pressure diff in Pa
+v=Cp*((2*delP)/rhoc)^0.5;//max vel at center
+Re=D*v*rhoc/mu;//Reynolds Number
+vr=0.85;//from the given graph the ratio of avg vel/max vel is 0.85
+vavg=vr*v;//the average velcity in m/s
+mprintf(" average velcity = %f m/s",vavg)
+A=(3.14/4)*(D*D);//cross sec area in m2
+V=A*vavg;//volumetric flow rate in m3/s
+mprintf("volumetric flow rate = %f m3/s",V)