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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2705/CH5/EX5.3 | |
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initial commit / add all books
Diffstat (limited to '2705/CH5/EX5.3')
| -rwxr-xr-x | 2705/CH5/EX5.3/Ex5_3.sce | 20 |
1 files changed, 20 insertions, 0 deletions
diff --git a/2705/CH5/EX5.3/Ex5_3.sce b/2705/CH5/EX5.3/Ex5_3.sce new file mode 100755 index 000000000..71188b43b --- /dev/null +++ b/2705/CH5/EX5.3/Ex5_3.sce @@ -0,0 +1,20 @@ +clear;
+clc;
+disp('Example 5.3');
+
+// aim : To determine
+// the new volume of the gas
+
+// Given values
+V1 = 10000;// [mm^3]
+T1 = 273+18;// [K]
+T2 = 273+85;// [K]
+
+// solution
+// since pressure exerted on the apparatus is constant so using charle's law V/T=constant
+// hence
+V2 = V1*T2/T1;// [mm^3]
+
+mprintf('\n The new volume of the gas trapped in the apparatus is = %f mm^3\n',V2);
+
+// End
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