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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2705/CH4/EX4.5/Ex4_5.sce | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '2705/CH4/EX4.5/Ex4_5.sce')
| -rwxr-xr-x | 2705/CH4/EX4.5/Ex4_5.sce | 25 |
1 files changed, 25 insertions, 0 deletions
diff --git a/2705/CH4/EX4.5/Ex4_5.sce b/2705/CH4/EX4.5/Ex4_5.sce new file mode 100755 index 000000000..c2c030046 --- /dev/null +++ b/2705/CH4/EX4.5/Ex4_5.sce @@ -0,0 +1,25 @@ +clear;
+clc;
+disp('Example 4.5');
+
+// aim : To determine
+// the specific enthalpy
+
+// Given values
+P = 70; // pressure, [kn/m^2]
+x = .85; // Dryness fraction
+
+// solution
+
+// from steam table, at given pressure
+hf = 376.8;// [kJ/kg]
+hfg = 2283.3;// [kJ/kg]
+
+// now using equation [2]
+h = hf+x*hfg;// specific enthalpy of wet steam,[kJ/kg]
+
+mprintf('\n The specific enthalpy of wet steam is = %f kJ/kg \n',h);
+
+// There is minor variation in the book's answer
+
+// End
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