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authorpriyanka2015-06-24 15:03:17 +0530
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+clear;
+clc;
+disp('Example 17.5');
+
+// aim : To determine
+// the brake power,indicated power and mechanicl efficiency
+// draw up an energy balance and as % age of the energy supplied
+
+// given values
+N = 50;// speed, [rev/s]
+BL = 267;// break load.,[N]
+BL1 = 178;// break load of cylinder cut1, [N]
+BL2 = 187;// break load of cylinder cut2, [N]
+BL3 = 182;// break load of cylinder cut3, [N]
+BL4 = 182;// break load of cylinder cut4, [N]
+
+FC = .568/130;// fuel consumption, [L/s]
+s = .72;// specific gravity of fuel
+CV = 43000;// calorific value of fuel, [kJ/kg]
+
+Te = 760;// exhaust temperature, [C]
+c = 1.015;// specific heat capacity of exhaust gas, [kJ/kg K]
+Ti = 18;// cooling water inlet temperature, [C]
+To = 56;// cooling water outlet temperature, [C]
+mw = .28;// cooling water flow rate, [kg/s]
+Ta = 21;// ambient tempearture, [C]
+C = 4.18;// specific heat capacity of cooling water, [kJ/kg K]
+
+// solution
+bp = BL*N/455;// brake power of engine, [kW]
+bp1 = BL1*N/455;// brake power of cylinder cut1, [kW]
+i1 = bp-bp1;// indicated power of cylinder cut1, [kW]
+bp2 = BL2*N/455;// brake power of cylinder cut2, [kW]
+i2 = bp-bp2;// indicated power of cylinder cut2, [kW]
+bp3 = BL3*N/455;// brake power of cylinder cut3, [kW]
+i3 = bp-bp3;// indicated power of cylinder cut3, [kW]
+bp4 = BL4*N/455;// brake power of cylinder cut4, [kW]
+i4 = bp-bp4;// indicated power of cylinder cut4, [kW]
+
+ip = i1+i2+i3+i4;// indicated power of engine, [kW]
+n_mec = bp/ip;// mechanical efficiency
+
+mprintf('\n The Brake power is = %f kW\n',bp);
+mprintf('\n The Indicated power is = %f kW\n',ip);
+mprintf('\n The mechanical efficiency is = %f percent\n',n_mec*100);
+
+mf = FC*s;// mass of fuel/s, [kg]
+ef = CV*mf;// energy from fuel/s, [kJ]
+me = 15*mf;// mass of exhaust/s,[kg],(given in condition)
+ee = me*c*(Te-Ta);// energy to exhaust/s,[kJ]
+ec = mw*C*(To-Ti);// energy to cooling water/s,[kJ]
+es = ef-(ee+ec+bp);// energy to surrounding,etc/s,[kJ]
+
+disp('Energy can be tabulated as :-');
+disp('----------------------------------------------------------------------------------------------------');
+disp(' kJ/s Percentage ')
+disp('----------------------------------------------------------------------------------------------------');
+mprintf('\n Energy from fuel %f %f\n Energy to brake power %f %f\n Energy to exhaust %f %f\n Energy to coolant %f %f\n Energy to suroundings,etc. %f %f\n',ef,ef/ef*100,bp,bp/ef*100,ee,ee/ef*100,ec,ec/ef*100,es,es/ef*100);
+
+// there is minor variation in the result reported in the book
+// End