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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Exa 3.4
+clc;
+clear;
+close;
+// Given data
+V_CC= 10;// in V
+V_CE= 5;// in V
+V_BE= 0.7;// in V
+I_C= 5*10^-3;// in mA
+bita= 100;
+R_C= (V_CC-V_CE)/I_C;// in Ω
+I_B= I_C/bita;// in A
+R_B= (V_CC-V_BE)/I_B;// in Ω
+disp(R_C*10^-3,"The value of R_C in kΩ is : ")
+disp(I_B*10^6,"The value of I_B in µA is : ")
+disp(R_B*10^-3,"The value of R_B in kΩ is : ")
+
+// Note: The value of base current in the book is wrong
+
+
+