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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Exa 3.20
+clc;
+clear;
+close;
+// Given data
+VBE= 0.7;// in V
+VCC= 10.7;// in V
+R_C= 10;//in kΩ
+R_C=R_C*10^3;// in Ω
+R_B= 10;//in kΩ
+R_B=R_B*10^3;// in Ω
+I1= (VCC-VBE)/R_C;// in A
+disp(I1*10^3,"The value of I1 in mA is : ")
+// Part (b)
+VC= -4;//in V
+VB= -10;// in V
+R_C= 5.6;//in kΩ
+R_C=R_C*10^3;// in Ω
+R_B= 2.4;//in kΩ
+R_B=R_B*10^3;// in Ω
+VCC=12;// V
+I_C= (VC-VB)/R_B;// in A
+V2= VCC- (R_C*I_C);
+disp(V2,"The value of V2 in volt is : ");
+// Part (c)
+VCC= 0;
+VCE= -10;// in V
+R_C= 10;//in kΩ
+R_C=R_C*10^3;// in Ω
+I_C= (VCC-VCE)/R_C;// in A
+V4= 1;// in V
+I3= I_C;// in A (approx)
+disp(V4,"The value of V4 in volt is : ");
+disp(I3*10^3,"The value of I3 in mA is : ")
+// Part (d)
+VBE= -10;// in V
+VCC= 10;// in V
+R_B= 5;//in kΩ
+R_B=R_B*10^3;// in Ω
+R_C= 15;//in kΩ
+R_C=R_C*10^3;// in Ω
+// I5= I_C and
+// I5= (V6-0.7-VBE)/R_B and I_C= (VCC-V6)/R_C
+V6= (VCC*R_B+R_C*(0.7+VBE))/(R_C+R_B);
+disp(V6,"The value of V6 in volt is : ")
+I5= (V6-0.7-VBE)/R_B;// in A
+disp(I5*10^3,"The value of I5 in mA is : ")
+
+