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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Exa 3.14
+clc;
+clear;
+close;
+// Given data
+bita=100;
+hFE= 100;
+VCEsat= 0.2;// in V
+VBEsat= 0.8;// in V
+VBEactive= 0.7;// in V
+VBB= 5;// in V
+VCC= 10;// in V
+R_C= 3;// in kΩ
+R_C=R_C*10^3;// in Ω
+R_B= 50;// in kΩ
+R_B=R_B*10^3;// in Ω
+// Formula VCC= ICsat*R_C+VCEsat
+ICsat= (VCC-VCEsat)/R_C;//A
+disp(ICsat*10^3,"The value of IC(sat) in mA is : ")
+IBmin= ICsat/bita;// in A
+// Apply KVL to input circuit, VBB= IB*R_B+VBEsat
+IB= (VBB-VBEsat)/R_B;// in A
+disp(IB*10^6,"Actual base current in µA is : ")