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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2642/CH8/EX8.5 | |
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initial commit / add all books
Diffstat (limited to '2642/CH8/EX8.5')
| -rwxr-xr-x | 2642/CH8/EX8.5/Ex8_5.sce | 33 |
1 files changed, 33 insertions, 0 deletions
diff --git a/2642/CH8/EX8.5/Ex8_5.sce b/2642/CH8/EX8.5/Ex8_5.sce new file mode 100755 index 000000000..b8f1f476f --- /dev/null +++ b/2642/CH8/EX8.5/Ex8_5.sce @@ -0,0 +1,33 @@ +// FUNDAMENTALS OF ELECTICAL MACHINES
+// M.A.SALAM
+// NAROSA PUBLISHING HOUSE
+// SECOND EDITION
+
+// Chapter 8 : STARTING, CONTROL AND TESTING OF AN INDUCTION MOTOR
+// Example : 8.5
+
+clc;clear; // clears the console and command history
+
+// Given data
+V = 210 // supply voltage in V
+f = 50 // supply frequency in Hz
+P = 50 // i/p power in W
+I_br = 2.5 // line current in A
+V_br = 25 // line voltgae
+R_1 = 2.4 // resistance between two resistance in ohm
+
+// caclulations
+V_br = V_br/sqrt(3) // phase voltage
+P_br = P/3 // power per phase in W
+R_eq = P_br/I_br^2 // equivalent resistance in ohm
+R_2 = R_eq-(R_1/2) // per phase rotor resistance in ohm
+Z_eq = V_br/I_br // equivalent impedance in ohm
+X_eq = sqrt(Z_eq^2-R_2^2) // equivalent reactance in ohm
+X_1 = 0.5*X_eq
+
+// display the result
+disp("Example 8.5 solution");
+printf(" \n Equivalent resistance \n R_eq = %.1f ohm \n", R_eq );
+printf(" \n Equivalent reactance \n X_eq = %.1f ohm \n", X_eq );
+printf(" \n Equivalent reactance \n X_1 = %.1f ohm \n", X_1 );
+
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