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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2642/CH7/EX7.7 | |
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initial commit / add all books
Diffstat (limited to '2642/CH7/EX7.7')
| -rwxr-xr-x | 2642/CH7/EX7.7/Ex7_7.sce | 35 |
1 files changed, 35 insertions, 0 deletions
diff --git a/2642/CH7/EX7.7/Ex7_7.sce b/2642/CH7/EX7.7/Ex7_7.sce new file mode 100755 index 000000000..8559c9eca --- /dev/null +++ b/2642/CH7/EX7.7/Ex7_7.sce @@ -0,0 +1,35 @@ +// FUNDAMENTALS OF ELECTICAL MACHINES
+// M.A.SALAM
+// NAROSA PUBLISHING HOUSE
+// SECOND EDITION
+
+// Chapter 7 : THREE-PHASE INDUCTION MOTOR
+// Example : 7.7
+
+clc;clear; // clears the console and command history
+
+// Given data
+V = 440 // supply voltage in V
+P = 6 // number of poles
+f = 50 // frequency in Hz
+P_a = 45000 // i/p power
+N_l = 900 // speed in rpm
+P_tloss = 2000 // total power loss in W
+
+// caclulations
+N_s = 120*f/P // synchronous speed in rpm
+s = (N_s-N_l)/N_s // slip
+P_ag = (P_a-P_tloss) // air gap power in W
+P_rcu = s*P_ag // rotor copper loss in W
+P_mech = P_ag-P_rcu // mechanical power in W
+P_0 = P_mech-3000 // o/p power in W
+n = (P_0/P_ag)*100 // efficiency since n = P_o/P_in
+
+// display the result
+disp("Example 7.7 solution");
+printf(" \n Slip \n s = %.1f \n", s );
+printf(" \n Rotor copper loss \n P_rcu = %.f W \n", P_rcu );
+printf(" \n Out put power \n P_0 = %.f W \n", P_0 );
+printf(" \n Efficiency \n n = %.f percent \n", n );
+
+
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