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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2642/CH6/EX6.1 | |
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initial commit / add all books
Diffstat (limited to '2642/CH6/EX6.1')
-rwxr-xr-x | 2642/CH6/EX6.1/Ex6_1.sce | 26 |
1 files changed, 26 insertions, 0 deletions
diff --git a/2642/CH6/EX6.1/Ex6_1.sce b/2642/CH6/EX6.1/Ex6_1.sce new file mode 100755 index 000000000..f4b8cdee5 --- /dev/null +++ b/2642/CH6/EX6.1/Ex6_1.sce @@ -0,0 +1,26 @@ +// FUNDAMENTALS OF ELECTICAL MACHINES
+// M.A.SALAM
+// NAROSA PUBLISHING HOUSE
+// SECOND EDITION
+
+// Chapter 6 : CONTROL AND STARTING OF A DC MOTORS
+// Example : 6.1
+
+clc;clear; // clears the console and command history
+
+// Given data
+V_t = 220 // supply voltage in V
+I_a1 = 10 // dc shunt motor armature current in A
+N_1 = 900 // speed in rpm
+R_a = 1 // armature resistance in ohm
+N_2 = 500 // speed in rpm
+
+// caclulations
+E_b1 = V_t-I_a1*R_a // initial back emf in V
+R = (E_b1/10)*(1-(N_2/N_1)) // additional value of resistance in ohm
+
+// display the result
+disp("Example 6.1 solution");
+printf(" \n additional value of resistance \n R = %.1f ohm \n", R);
+
+
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