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authorpriyanka2015-06-24 15:03:17 +0530
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+// FUNDAMENTALS OF ELECTICAL MACHINES
+// M.A.SALAM
+// NAROSA PUBLISHING HOUSE
+// SECOND EDITION
+
+// Chapter 5 : DIRECT CURRENT MOTORS
+// Example : 5.2
+
+clc;clear; // clears the console and command history
+// Given data
+I = 20 // total current in A
+V_t = 250; // supply voltage in volt
+R_sh = 200; // shunt field resistance in Ω
+R_a = 0.3; // armature resistance in Ω
+
+// caclulations
+ I_sh = V_t/R_sh; // shunt field current in A
+ I_a = I-I_sh' // armature current
+ E_b = V_t - R_a*I_a; // the back emf in V
+ P_md = E_b*I_a; // mechanical power developed in W
+
+ // display the result
+disp("Example 5.2 solution");
+printf("\n The back emf is \n E_b = %.1f V \n\n",E_b );
+printf(" \n Mechanical power developed is \n P_md = %.1f W" ,P_md );
+printf(" \n NOTE : error in calculation they has taken I_a=18.13, instead of I_a=18.75");