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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2642/CH3/EX3.13 | |
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initial commit / add all books
Diffstat (limited to '2642/CH3/EX3.13')
| -rwxr-xr-x | 2642/CH3/EX3.13/Ex3_13.sce | 29 |
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diff --git a/2642/CH3/EX3.13/Ex3_13.sce b/2642/CH3/EX3.13/Ex3_13.sce new file mode 100755 index 000000000..3ce3efd85 --- /dev/null +++ b/2642/CH3/EX3.13/Ex3_13.sce @@ -0,0 +1,29 @@ +// FUNDAMENTALS OF ELECTICAL MACHINES
+// M.A.SALAM
+// NAROSA PUBLISHING HOUSE
+// SECOND EDITION
+
+// Chapter 3 : TRANSFORMER AND PER UNIT SYSTEM
+// Example : 3.13
+
+clc;clear; // clears the console and command history
+
+// Given data
+kVA = 120 // kVA ratings of autotransformer
+V1 = 2200 // lower part voltage of autotransformer in V
+V2 = 220 // upper part voltage of autotransformer in V
+
+// caclulations
+I_pq = kVA*10^3/V2 // currents of respective windings
+I_qr = kVA*10^3/V1 // currents of respective windings
+I_1 = I_pq+I_qr // current in primary side in A
+V_2 = V1+V2 // voltage across the secondary side in V
+kVA_1 = I_1*V1/1000 // kVA ratings of autotrnsformer
+kVA_2 = I_pq*V_2/1000 // kVA ratings of autotrnsformer
+
+
+// display the result
+disp("Example 3.13 solution");
+printf(" \n kVA ratings of autotrnsformer \n kVA_1 = %.0f kVA \n", kVA_1);
+printf(" \n kVA ratings of autotrnsformer \n kVA_2 = %.0f kVA \n", kVA_2);
+
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