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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /2642/CH3/EX3.10 | |
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initial commit / add all books
Diffstat (limited to '2642/CH3/EX3.10')
| -rwxr-xr-x | 2642/CH3/EX3.10/Ex3_10.sce | 38 |
1 files changed, 38 insertions, 0 deletions
diff --git a/2642/CH3/EX3.10/Ex3_10.sce b/2642/CH3/EX3.10/Ex3_10.sce new file mode 100755 index 000000000..2f3d2ebc6 --- /dev/null +++ b/2642/CH3/EX3.10/Ex3_10.sce @@ -0,0 +1,38 @@ +// FUNDAMENTALS OF ELECTICAL MACHINES
+// M.A.SALAM
+// NAROSA PUBLISHING HOUSE
+// SECOND EDITION
+
+// Chapter 3 : TRANSFORMER AND PER UNIT SYSTEM
+// Example : 3.10
+
+
+clc;clear; // clears the console and command history
+
+// Given data
+kVA = 12 // kVA ratingss of transformer
+n = 0.97 // maximum efficiency at unity power factor
+t_1 = 8 // time in hours
+P_1 = 10 // load in kW
+pf_1 = 0.8 // lagging power factor
+t_2 = 10 // time in hours
+P_2 = 15 // load in kW
+pf_2 = 0.90 // leading power factor
+t_3 = 6 // time in hours at no load
+P_3 = 0 // load in kW
+
+// caclulations
+P_01 = kVA*1 // o/p power at full load and unity factor in kW
+P_in1 = (P_01/n) // i/p power at full load
+P_tloss = P_in1-P_01 // total loss in kW
+P_cu = P_tloss/2 // copper loss at 12 kVA P_cu=P_i in kW
+P_024 = P_1*t_1+P_2*t_2+P_3*t_3 // all day o.p power in kWh
+P_i24 = 24*P_cu // iron loss for 24 hours in kWh
+P_cu24 = P_cu*t_1*((P_1/pf_1)/P_01)^2+P_cu*t_2*((P_2/pf_2)/P_01)^2 // copper loss for 24 hours
+P_in24 = P_024+P_i24+P_cu24 // all day i/p power in kWh
+n_allday = (P_024/P_in24)*100 // all day efficiency
+
+// display the result
+disp("Example 3.10 solution");
+printf(" \n All day efficiency \n n_allday = %.0f percent \n", n_allday);
+
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