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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Example 7.5
+clc;
+clear;
+close;
+// Given data
+format('v',5);
+alpha= 1.414;// passband
+C= 0.01*10^-6;// in F (assume)
+fc= 1*10^3;// in Hz
+dc_gain= 6;
+R= 1/(2*%pi*C*fc);// in Ω
+R= R*10^-3;// in kΩ
+disp("The value of R is : "+string(R)+" kΩ (standard value 15 kΩ)");
+R= 15;// in kΩ
+Af= 3-alpha;// and Af= 1+Rf/R1 or
+// Rf= (Af-1)*R1 (i)
+// 2*R= Rf || R1, hence from (i)
+R1= 2*R*Af/(Af-1);// in kΩ
+disp("The value of R1 is : "+string(R1)+" kΩ (standard value 82 kΩ)");
+R1= 82;// in kΩ
+Rf= (Af-1)*R1;// in kΩ
+disp("The value of Rf is : "+string(Rf)+" kΩ (standard value 47 kΩ)");
+Aamp= dc_gain/Af;
+disp("The value of Aamp is : "+string(Aamp));