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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+//Eg-12.5
+//pg-515
+
+clear
+clc
+
+x = [0;0.5;1.2];
+T = [450;388;325];
+
+//The derivative can be computed using the equation [19]
+//Therefore the derivative at x = 1
+
+D = ((2-0.5-1.2)/((0-0.5)*(0-1.2)))*450 + ((2-0-1.2)/((0.5-0)*(0.5-1.2)))*388 + ((2-0-0.5)/((1.2-0)*(1.2-0.5)))*325;
+
+printf('The value of derivative at x = 1 is %f',D)